April 29, 2013 - 11:18am
Combination Hydration Equation
I need help. I've committed to 30 loaves of bread for the Church sale on Saturday. My plan was to pre-ferment a large quantity of high hydration dough-easier on the mixer--and use it to improve the smaller quantities of lower hydration dough. Good plan, huh? But...
Now I have a large batch of 87% hydration first dough, "x", and want to mix it with 55% hydration second dough, "y", to end up with a 60% hydration final dough, "z". I've let my math skills get rusty, or maybe I'm just getting old, but I cannot quite set up the equation I need.
How many oz of "x" and how many of "y" are needed to yield 32 oz of "z"?
Help, O Wise Ones!!
Ju-Ju
Final dough hydration: (0.87/1.87*x+0.55/1.55*y)/(x/1.87+y/1.55) = 0.60 => y = 1.553 x
x + y = 32 (oz)
so x = 12.53 oz, y = 19.47 oz